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CIE 9231 2022 June Paper 33 Q1

A Level / CIE / FM

CIE 9231 2022 June Paper 33 Paper · Question 1

题目

Problem

A uniform lamina OABCOABC is a trapezium whose vertices can be represented by coordinates in the xx-yy plane. The coordinates of the vertices are O(0,0)O(0,0), A(15,0)A(15,0), B(9,4)B(9,4) and C(3,4)C(3,4).

Find the xx-coordinate of the centre of mass of the lamina.

(4)
题目中文翻译

一块均匀薄片 OABCOABC 的形状为梯形,其顶点可以用 xx-yy 平面内的坐标表示。各顶点的坐标为 O(0,0)O(0,0)、A(15,0)A(15,0)、B(9,4)B(9,4) 和 C(3,4)C(3,4)。

求该薄片质心的 xx 坐标。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

解法一

思路

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从 BB、CC 向 xx 轴作垂线,把梯形分成一个矩形和两个直角三角形。用面积为权重计算关于 yy 轴的矩。

答题过程

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Let D=(3,0)D=(3,0) and E=(9,0)E=(9,0). The left triangle OCDOCD has area 66 and centroid at x=(0+3+3)/3=2x=(0+3+3)/3=2. The rectangle between x=3x=3 and x=9x=9 has area 2424 and centroid at x=6x=6. The right triangle BAEBAE has area 1212 and centroid at x=(9+15+9)/3=11x=(9+15+9)/3=11. Therefore

x‾= 6(2)+24(6)+12(11)6+24+12= 12+144+13242= 28842=487.\begin{align*} \overline{x}=&\,\frac{6(2)+24(6)+12(11)}{6+24+12}\\[4mm] =&\,\frac{12+144+132}{42}\\[4mm] =&\,\frac{288}{42}=\frac{48}{7}. \end{align*}