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CIE 9231 2025 November Paper 33 Q5

A Level / CIE / FM

CIE 9231 2025 Nov Paper 33 Paper · Question 5

题目

Problem

A uniform lamina OABCDOABCD consists of a rectangle OACDOACD and a triangle ABCABC. The length of OAOA is kaka, the length of ODOD is 2a2a, the height of triangle ABCABC is hh and angle CABCAB is 4545^\circ (see diagram). Relative to axes through OO, parallel and perpendicular to OAOA as shown, the centre of mass of triangle ABCABC is (xˉ,yˉ)(\bar{x},\bar{y}).

(a) Show that

xˉ=13(3ka+h),\bar{x}=\frac13(3ka+h),

and find an expression for yˉ\bar{y}.

(3)

The lamina OABCDOABCD is placed vertically on its edge OAOA on a horizontal plane.

(b) Find, in terms of aa and kk, the set of values of hh for which the lamina is in equilibrium.

(4)

It is now given that k=33k=\frac{\sqrt3}{3} and that the lamina is on the point of toppling.

(c) Find, in terms of aa, the coordinates of the centre of mass of the triangle ABCABC.

(2)
题目中文翻译

均匀薄片 OABCDOABCD 由矩形 OACDOACD 和三角形 ABCABC 构成。OAOA 的长度为 kakaODOD 的长度为 2a2a,三角形 ABCABC 的高为 hh,且角 CABCAB4545^\circ(见图)。相对于如图所示经过 OO、分别平行和垂直于 OAOA 的坐标轴,三角形 ABCABC 的质心为 (xˉ,yˉ)(\bar{x},\bar{y})

(a) 证明

xˉ=13(3ka+h),\bar{x}=\frac13(3ka+h),

并求 yˉ\bar{y} 的表达式。

将薄片 OABCDOABCD 竖直放置在水平面上的边 OAOA 上。

(b) 用 aakk 表示使薄片处于平衡的 hh 的取值集合。

现已知 k=33k=\frac{\sqrt3}{3},且薄片正处于倾倒临界状态。

(c) 用 aa 表示三角形 ABCABC 质心的坐标。

解答