(a) Find the set of values of k for which A is non-singular.
(3)
(b) Given that A is non-singular, find, in terms of k, the entries in the top row of A−1.
(4)
(c) Given that B=(100100), give an example of a matrix C such that BAC=(2k14).
(4)
(d) Find the set of values of k for which the transformation in the x–y plane represented by (2k14) has two distinct invariant lines through the origin.
(6)
题目中文翻译
矩阵 A 为
A=1472k8369.
(a) 求使 A 为非奇异矩阵的 k 的取值集合。
(3)
(b) 已知 A 为非奇异矩阵,用 k 表示 A−1 第一行的各元素。
(4)
(c) 已知 B=(100100),给出一个矩阵 C 的例子,使得 BAC=(2k14)。
(4)
(d) 求使矩阵 (2k14) 所表示的 x–y 平面内的变换具有两条经过原点的不同不变直线的 k 的取值集合。
(6)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
Thus A is non-singular when 60−12k=0, giving k=5.
(b)
解法一
思路
展开
逆矩阵第一行来自余因子矩阵的第一列;注意转置与第二个余因子的负号。
答题过程
展开
Since A−1=(detA)−1(cofA)T, its top row uses the cofactors C11,C21,C31:
C11=C21=C31=9k−48,−(18−24)=6,12−3k.
Hence the required row is
60−12k1(9k−48612−3k),k=5.
(c)
解法一
思路
展开
左乘 B 选出前两行;右边只需把所得矩阵的前两列交换,并舍去第三列。直接写出实现这个操作的矩阵并验算。
答题过程
展开
First,
BA=(142k36).
Choose
C=010100.
Then
BAC==(142k36)010100(2k14),
as required.
(d)
解法一
思路
展开
先求不变方向的两个实斜率,再排除其中一条直线被压成原点的情形;两个不同的实斜率本身还不够。
答题过程
展开
A nonvertical line through the origin has equation y=mx. Under the transformation,
(x′y′)==(2k14)(xmx)((2+m)x(k+4m)x).
For its image to be the same line, k+4m=m(2+m), with 2+m=0. Thus
m2−2m−k=0.
Two distinct real slopes require
(−2)2−4(1)(−k)>0⟹k>−1.
Their values are m=1±1+k, and the scale factors along these directions are
2+m=3±1+k.
For k>−1, one of these vanishes precisely when k=8. At k=8, the direction m=−2 is mapped entirely to the origin, so it does not give a line mapped onto itself. This value must be excluded.
The vertical line is not invariant: (0,y) maps to (y,4y), which is not vertical. Therefore no additional invariant line was omitted, and the required set is