题目
Problem
Let A=(10a1), where a is a positive constant.
(a) State the type of the geometrical transformation in the x–y plane represented by A.
(1)
(b) Prove by mathematical induction that, for all positive integers n,
An=(10na1).
(5)
Let B=(ba−1ba−1), where b is a positive constant.
(c) Find the equations of the invariant lines, through the origin, of the transformation in the x–y plane represented by AnB.
(6)
题目中文翻译
设 A=(10a1),其中 a 是正常数。
(a) 写出 A 所表示的 x–y 平面内的几何变换的类型。
(1)
(b) 用数学归纳法证明,对于所有正整数 n,
An=(10na1).
(5)
设 B=(ba−1ba−1),其中 b 是正常数。
(c) 求 AnB 所表示的 x–y 平面内的变换的、经过原点的不变直线的方程。
(6)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
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观察坐标变换:纵坐标不变,横坐标增加与纵坐标成比例的量。
答题过程
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The transformation is (x,y)↦(x+ay,y). It is a shear in the x-direction, with the x-axis fixed and shear factor a.
(b)
解法一
思路
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归纳法必须写出初始情形、明确的归纳假设、矩阵乘法及最终结论。
答题过程
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For n=1,
A1=(10a1),
so the formula holds.
Assume that for some positive integer k,
Ak=(10ka1).
Then
Ak+1===(10ka1)(10a1)(10a+ka1)(10(k+1)a1).
Thus the formula holds for k+1 whenever it holds for k. By mathematical induction,
An=(10na1)
for every positive integer n.