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CIE 9231 2024 June Paper 23 Q2

A Level / CIE / FP2

CIE 9231 2024 June Paper 23 Paper · Question 2

题目

Problem

The curve CC has parametric equations

x=cosht,y=sinht,for 0<t35.x=\cosh t,\qquad y=\sinh t,\qquad\text{for }0<t\le\frac{3}{5}.

The length of CC is denoted by ss.

(a) Show that

s=035cosh2tdt.s=\int_0^{\frac{3}{5}}\sqrt{\cosh 2t}\,\mathrm{d}t.
[4]

(b) By finding the Maclaurin’s series for cosh2t\sqrt{\cosh 2t} up to and including the term in t2t^2, deduce an approximation to ss.

[5]
题目中文翻译

曲线 CC 的参数方程为

x=coshty=sinht0<t35x=\cosh t\qquad y=\sinh t\qquad 0<t\le\frac{3}{5}

曲线 CC 的长度记为 ss

(a) 证明

s=035cosh2tdts=\int_0^{\frac{3}{5}}\sqrt{\cosh 2t}\,\mathrm{d}t

(b) 求 cosh2t\sqrt{\cosh 2t} 的 Maclaurin 级数,展开至并包括 t2t^2 项,并据此推出 ss 的一个近似值。

解答