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CIE 9231 2024 June Paper 23 Q5

A Level / CIE / FP2

CIE 9231 2024 June Paper 23 Paper · Question 5

题目

Problem

(a) Find the general solution of the differential equation

d2xdt2+10dxdt+25x=338sint.\frac{\mathrm{d}^2x}{\mathrm{d}t^2}+10\frac{\mathrm{d}x}{\mathrm{d}t}+25x=338\sin t.
[7]

(b) Show that, for large positive values of tt and for any initial conditions,

xRsin(tφ),x\sim R\sin(t-\varphi),

where the constants RR and φ\varphi are to be determined.

[3]
题目中文翻译

(a) 求微分方程

d2xdt2+10dxdt+25x=338sint\frac{\mathrm{d}^2x}{\mathrm{d}t^2}+10\frac{\mathrm{d}x}{\mathrm{d}t}+25x=338\sin t

的通解。

(b) 证明对于较大的正 tt 值以及任意初始条件,

xRsin(tφ)x\sim R\sin(t-\varphi)

其中常数 RRφ\varphi 待确定。

解答