Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9231 2025 June Paper 21 Q2

A Level / CIE / FP2

CIE 9231 2025 June Paper 21 Paper · Question 2

题目

Problem

Let In=01(1x)nsinhxdxI_n = \int_0^1 (1 - x)^n\sinh x\,\mathrm{d}x, where nn is a non-negative integer.

(a) Show that, for n2n \ge 2, In=1+n(n1)In2I_n = -1 + n(n - 1)I_{n - 2}.

[4]

(b) Find the exact value of I2I_2.

[3]
题目中文翻译

In=01(1x)nsinhxdxI_n = \int_0^1 (1 - x)^n\sinh x\,\mathrm{d}x,其中 nn 是非负整数。

(a) 证明当 n2n \ge 2 时,In=1+n(n1)In2I_n = -1 + n(n - 1)I_{n - 2}

(b) 求 I2I_2 的精确值。

解答