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CIE 9231 2025 June Paper 23 Q2

A Level / CIE / FP2

CIE 9231 2025 June Paper 23 Paper · Question 2

题目

Problem

(a) Starting from the definitions of tanh\tanh and sech\operatorname{sech} in terms of exponentials, prove that

tanh2t+sech2t=1.\tanh^2 t + \operatorname{sech}^2 t = 1.
[3]

(b) The curve CC has parametric equations

x=ln(cosht),y=tan1(sinht),for 0t1.\begin{align*} x =&\, \ln(\cosh t), \quad y = \tan^{-1}(\sinh t), \quad \text{for } 0 \le t \le 1. \end{align*}

Find the length of CC.

[5]
题目中文翻译

(a) 从 tanh\tanhsech\operatorname{sech} 用指数表示的定义出发,证明

tanh2t+sech2t=1.\tanh^2 t + \operatorname{sech}^2 t = 1.

(b) 曲线 CC 的参数方程为

x=ln(cosht),y=tan1(sinht),for 0t1.\begin{align*} x =&\, \ln(\cosh t), \quad y = \tan^{-1}(\sinh t), \quad \text{for } 0 \le t \le 1. \end{align*}

CC 的长度。

解答