Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9231 2025 June Paper 24 Q5

A Level / CIE / FP2

CIE 9231 2025 June Paper 24 Paper · Question 5

题目

Problem

(a) Use de Moivre’s theorem to show that

sin7θ=64sin7θ+112sin5θ56sin3θ+7sinθ.\sin 7\theta = -64\sin^7\theta + 112\sin^5\theta - 56\sin^3\theta + 7\sin\theta.
[5]

(b) Hence find all roots of the equation

64x6112x4+56x27=064x^6 - 112x^4 + 56x^2 - 7 = 0

in the form sinqπ\sin q\pi, where qq is a rational number.

[3]
题目中文翻译

(a) 使用 De Moivre 定理证明

sin7θ=64sin7θ+112sin5θ56sin3θ+7sinθ\sin 7\theta = -64\sin^7\theta + 112\sin^5\theta - 56\sin^3\theta + 7\sin\theta

(b) 据此求方程

64x6112x4+56x27=064x^6 - 112x^4 + 56x^2 - 7 = 0

的全部根,并将其写成 sinqπ\sin q\pi 的形式,其中 qq 为有理数。

解答