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CIE 9231 2026 June Paper 22 Q1

A Level / CIE / FP2

CIE 9231 2026 June Paper 22 Paper · Question 1

题目

Problem

Find the first three terms in the Maclaurin’s series for sinh⁡−1(x+1)\sinh^{-1}(x+1) in the form ln⁡a+bx+cx2\ln a+bx+cx^2, giving the exact values of the constants aa, bb and cc.

(5)
题目中文翻译

求 sinh⁡−1(x+1)\sinh^{-1}(x+1) 的麦克劳林级数的前三项,写成 ln⁡a+bx+cx2\ln a+bx+cx^2 的形式,并给出常数 aa、bb 和 cc 的精确值。

(5)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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先用反双曲正弦的对数形式求常数项。再对 x+1x+1 使用链式法则,计算前两阶导数在零点的值。

答题过程

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For f(x)=arsinh⁡(x+1)f(x)=\operatorname{arsinh}(x+1),

f′(x)= 11+(x+1)2,f′′(x)= −x+1[1+(x+1)2]3/2.\begin{align*} f'(x)=&\,\frac1{\sqrt{1+(x+1)^2}},\\ f''(x)=&\,-\frac{x+1}{[1+(x+1)^2]^{3/2}}. \end{align*}

Thus f(0)=ln⁡(1+2)f(0)=\ln(1+\sqrt2), f′(0)=1/2f'(0)=1/\sqrt2 and f′′(0)=−1/(22)f''(0)=-1/(2\sqrt2). Here f(0)=arsinh⁡1=ln⁡(1+12+1)f(0)=\operatorname{arsinh}1=\ln(1+\sqrt{1^2+1}). Using f(x)=f(0)+xf′(0)+12x2f′′(0)+O(x3)f(x)=f(0)+xf'(0)+\frac12x^2f''(0)+O(x^3), the expansion is

f(x)=ln⁡(1+2)+x2−x242+O(x3).f(x)=\ln(1+\sqrt2)+\frac{x}{\sqrt2}-\frac{x^2}{4\sqrt2}+O(x^3).

Hence (a,b,c)=(1+2,1/2,−1/(42))(a,b,c)=\big(1+\sqrt2,1/\sqrt2,-1/(4\sqrt2)\big).