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CIE 9231 2026 June Paper 24 Q1

A Level / CIE / FP2

CIE 9231 2026 June Paper 24 Paper · Question 1

题目

Problem

(a) Find the set of values of kk for which the system of equations

3x+ky+7z= 1,8x+y+2z= 2,8x+2y+4z= 3,\begin{align*} 3x+ky+7z =&\, 1,\\ 8x+y+2z =&\, 2,\\ 8x+2y+4z =&\, 3, \end{align*}

has a unique solution and interpret this situation geometrically.

(4)

(b) Given that k=72k=\frac{7}{2}, show that the system of equations in part 1(a) is inconsistent and interpret this situation geometrically.

(2)
题目中文翻译

(a) 求使方程组

3x+ky+7z= 1,8x+y+2z= 2,8x+2y+4z= 3,\begin{align*} 3x+ky+7z =&\, 1,\\ 8x+y+2z =&\, 2,\\ 8x+2y+4z =&\, 3, \end{align*}

有唯一解的 kk 的取值集合,并从几何角度解释这种情况。

(4)

(b) 已知 k=72k=\frac{7}{2},证明 1(a) 中的方程组无解,并从几何角度解释这种情况。

(2)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

先用第三行减去第二行的两倍。新的一行只有一个非零项,沿这一行展开可直接找出使行列式为零的参数。

答题过程

展开

Subtracting twice the second row from the third, the coefficient determinant becomes

det⁡(3k7812−800)=−8(2k−7).\det\begin{pmatrix}3&k&7\\8&1&2\\-8&0&0\end{pmatrix} =-8(2k-7).

Thus the system has a unique solution for k∈R∖{72}\boxed{k\in\mathbb R\setminus\{\frac72\}}. In this case the three planes intersect at a single point.

(b)

解法一

思路

展开

后两式可以确定 xx 和 y+2zy+2z,把它们代回第一式检查。再用各个法向量判断两两相交的直线方向。

答题过程

展开

Subtracting twice the second equation from the third gives −8x=−1-8x=-1, so x=18x=\frac18 and the second equation gives y+2z=1y+2z=1. The left-hand side of the first equation is then

3x+72(y+2z)=38+72=318≠1.3x+\frac72(y+2z)=\frac38+\frac72=\frac{31}{8}\ne1.

The system is inconsistent. The normals are pairwise non-parallel, so each pair of planes intersects in a line. All three normals are perpendicular to (0,−2,1)(0,-2,1), so these three distinct intersection lines are parallel, forming the edges of a triangular prism.