题目
Problem
(a) Starting from the definitions of cosh and sinh in terms of exponentials, prove that
sinh2x=2sinhxcoshx.
[3]
(b) Using the substitution u=sinhx, find
∫sinh22xcoshxdx.
[4]
(c) Find the particular solution of the differential equation
dxdy+ytanhx=sinh22x,
given that y=4 when x=0. Give your answer in the form y=f(x).
[7]
题目中文翻译
(a) 从用指数表示的 cosh 和 sinh 的定义出发,证明
sinh2x=2sinhxcoshx
(b) 使用代换 u=sinhx,求
∫sinh22xcoshxdx
(c) 求微分方程
dxdy+ytanhx=sinh22x
的特解,已知当 x=0 时 y=4。将答案写成 y=f(x) 的形式。
解答