Find the particular solution of the differential equation
3dx2d2y+2dxdy+y=x2,
given that, when x=0, y=dxdy=0.
[10]
题目中文翻译
求微分方程
3dx2d2y+2dxdy+y=x2
的特解,已知当 x=0 时,y=dxdy=0。
(10)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
The auxiliary equation 3m2+2m+1=0 gives m=−31±32i. The complementary function is
e−x/3(Acos32x+Bsin32x).
For a particular integral yp=px2+qx+r, we have yp′=2px+q and yp′′=2p. Substituting and comparing coefficients gives p=1, 4p+q=0 and 6p+2q+r=0. Hence the particular integral is x2−4x+2. Write w=2/3. The general solution and its derivative are