题目
Problem
(a) Show that
dxd(ln(tanhx))=2cosech2x.
[3]
(b) Find the solution of the differential equation
sinh2xdxdy+2y=sinh2x
for which y=5 when x=ln2. Give your answer in an exact form.
[7]
题目中文翻译
(a) 证明
dxd(ln(tanhx))=2cosech2x
(b) 求微分方程
sinh2xdxdy+2y=sinh2x
的解,使得当 x=ln2 时 y=5。用精确形式给出答案。
解答