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CIE 9231 2025 Nov Paper 21 Q3

A Level / CIE / FP2

CIE 9231 2025 Nov Paper 21 Paper · Question 3

题目

Problem

The integral InI_n is defined by

In=01(1+x2)ndx.I_n = \int_0^1 \big(1 + x^2\big)^n \,\mathrm{d}x.

(a) By considering ddx(x(1+x2)n)\frac{\mathrm{d}}{\mathrm{d}x}\big(x(1 + x^2)^n\big), or otherwise, show that

(2n+1)In=2n+2nIn1.(2n + 1)I_n = 2^n + 2nI_{n - 1}.
[5]

(b) Find the exact value of I2I_{-2}.

[4]
题目中文翻译

积分 InI_n 定义为

In=01(1+x2)ndx.I_n = \int_0^1 \big(1 + x^2\big)^n \,\mathrm{d}x.

(a) 通过考虑 ddx(x(1+x2)n)\frac{\mathrm{d}}{\mathrm{d}x}\big(x(1 + x^2)^n\big),或用其他方法,证明

(2n+1)In=2n+2nIn1.(2n + 1)I_n = 2^n + 2nI_{n - 1}.

(b) 求 I2I_{-2} 的精确值。

解答