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CIE 9231 2025 Nov Paper 24 Q1

A Level / CIE / FP2

CIE 9231 2025 Nov Paper 24 Paper · Question 1

题目

Problem

It is given that In=01xnsinhxdxI_n = \int_0^1 x^n\sinh x\,\mathrm{d}x, where nn is a non-negative integer.

(a) Show that, for n2n \ge 2,

In=cosh1nsinh1+n(n1)In2.I_n = \cosh 1 - n\sinh 1 + n(n - 1)I_{n - 2}.
[3]

(b) Find the exact value of I2I_2.

[2]
题目中文翻译

已知 In=01xnsinhxdxI_n = \int_0^1 x^n\sinh x\,\mathrm{d}x,其中 nn 是非负整数。

(a) 证明当 n2n \ge 2 时,

In=cosh1nsinh1+n(n1)In2.I_n = \cosh 1 - n\sinh 1 + n(n - 1)I_{n - 2}.

(b) 求 I2I_2 的精确值。

解答