题目
Problem
(a) Find the general solution of the differential equation
dx2d2y+dxdy+y=sin2x+cos2x.
[7]
(b) For large positive values of x and for any initial conditions, show that the solution to part (a) can be approximated by
y≈Rsin(2x−ϕ),
where R and ϕ are positive constants to be determined.
[3]
题目中文翻译
(a) 求微分方程
dx2d2y+dxdy+y=sin2x+cos2x.
的通解。
(b) 对于较大的正 x,并且对任意初始条件,证明 (a) 中的解可以近似为
y≈Rsin(2x−ϕ),
其中 R 和 ϕ 是需要确定的正常数。
解答