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CIE 9231 2022 June Paper 43 Q1

A Level / CIE / FS

CIE 9231 2022 June Paper 43 Paper · Question 1

题目

Problem

The times taken by members of a large quiz club to complete a challenge have a normal distribution with mean μ\mu minutes. The times, xx minutes, are recorded for a random sample of 8 members of the club. The results are summarised as follows, where xˉ\bar{x} is the sample mean.

xˉ=33.8∑(x−xˉ)2=94.5\bar{x} = 33.8 \qquad \sum (x - \bar{x})^2 = 94.5

Find a 95% confidence interval for μ\mu.

[4]
题目中文翻译

一个大型问答俱乐部的成员完成一项挑战所需时间服从正态分布,均值为 μ\mu 分钟。从该俱乐部成员中随机抽取 8 人,记录他们所需的时间 xx 分钟。结果汇总如下,其中 xˉ\bar{x} 是样本均值。

xˉ=33.8∑(x−xˉ)2=94.5\bar{x} = 33.8 \qquad \sum (x - \bar{x})^2 = 94.5

求 μ\mu 的 95% 置信区间。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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题目给出样本均值和平方离差和。先求无偏方差,再用自由度为 77 的 tt 临界值。

答题过程

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The sample variance is s2=94.5/(8−1)=13.5s^2=94.5/(8-1)=13.5. The two-sided 95%95\% critical value for 77 degrees of freedom is 2.3652.365. Hence the confidence interval is

 33.8±2.36513.5/8= (30.72777…,36.87222…),\begin{align*} &\,33.8\pm2.365\sqrt{13.5/8}\\ =&\,(30.72777\ldots,36.87222\ldots), \end{align*}

or (30.7,36.9)(30.7,36.9) minutes to three significant figures.