题目
The children at two large schools, P and Q, are all given the same puzzle to solve. A random sample of size 10 is taken from the children at school P. Their individual times to complete the puzzle give a sample mean of 9.12 minutes and an unbiased variance estimate of minutes. A random sample of size 12 is taken from the children at school Q. Their individual times, minutes, to complete the puzzle are summarised by
where is the sample mean. Times to complete the puzzle are assumed to be normally distributed with the same population variance.
Test at the 5% significance level whether the population mean time taken to complete the puzzle by children at school P is greater than the population mean time taken to complete the puzzle by children at school Q.
题目中文翻译
两所大学校 P 和 Q 的孩子都要解同一个谜题。从学校 P 的孩子中随机抽取容量为 10 的样本,他们各自完成谜题的时间给出的样本均值为 9.12 分钟,无偏方差估计为 分钟。从学校 Q 的孩子中随机抽取容量为 12 的样本,他们完成谜题的个人时间为 分钟,汇总为
其中 是样本均值。假设完成谜题的时间服从正态分布,且具有相同的总体方差。
在 5% 显著性水平下,检验学校 P 的孩子完成谜题所需的总体平均时间是否大于学校 Q 的孩子完成谜题所需的总体平均时间。