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CIE 9231 2023 June Paper 41 Q2

A Level / CIE / FS

CIE 9231 2023 June Paper 41 Paper · Question 2

题目

Problem

The children at two large schools, P and Q, are all given the same puzzle to solve. A random sample of size 10 is taken from the children at school P. Their individual times to complete the puzzle give a sample mean of 9.12 minutes and an unbiased variance estimate of 2.162.16 minutes2^2. A random sample of size 12 is taken from the children at school Q. Their individual times, xx minutes, to complete the puzzle are summarised by

x=99.6(xxˉ)2=21.5,\sum x = 99.6 \qquad \sum (x - \bar{x})^2 = 21.5,

where xˉ\bar{x} is the sample mean. Times to complete the puzzle are assumed to be normally distributed with the same population variance.

Test at the 5% significance level whether the population mean time taken to complete the puzzle by children at school P is greater than the population mean time taken to complete the puzzle by children at school Q.

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题目中文翻译

两所大学校 P 和 Q 的孩子都要解同一个谜题。从学校 P 的孩子中随机抽取容量为 10 的样本,他们各自完成谜题的时间给出的样本均值为 9.12 分钟,无偏方差估计为 2.162.16 分钟2^2。从学校 Q 的孩子中随机抽取容量为 12 的样本,他们完成谜题的个人时间为 xx 分钟,汇总为

x=99.6(xxˉ)2=21.5,\sum x = 99.6 \qquad \sum (x - \bar{x})^2 = 21.5,

其中 xˉ\bar{x} 是样本均值。假设完成谜题的时间服从正态分布,且具有相同的总体方差。

在 5% 显著性水平下,检验学校 P 的孩子完成谜题所需的总体平均时间是否大于学校 Q 的孩子完成谜题所需的总体平均时间。

解答