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CIE 9231 2023 June Paper 43 Q3

A Level / CIE / FS

CIE 9231 2023 June Paper 43 Paper · Question 3

题目

Problem

A large number of students took two test papers in mathematics. The teacher believes that the marks obtained in Paper 1 will be higher than the marks obtained in Paper 2. She chooses a random sample of 9 students and compares their marks. The marks are shown in the table.

StudentABCDEFGHI
Paper 1467355648642666860
Paper 2416661639040584270

(a) Carry out a Wilcoxon matched-pairs signed-rank test, at the 5% significance level, to test whether the data supports the teacher’s belief.

[7]

(b) State an assumption that you have made in carrying out the test in part (a).

[1]
题目中文翻译

大量学生参加了两份数学测试卷。老师认为 Paper 1 的得分会高于 Paper 2 的得分。她随机抽取 9 名学生并比较他们的分数。分数如下表所示。

学生ABCDEFGHI
Paper 1467355648642666860
Paper 2416661639040584270

(a) 在 5% 显著性水平下,进行 Wilcoxon 配对符号秩检验,检验数据是否支持老师的看法。

(7)

(b) 说明你在进行 part (a) 中的检验时所作的一个假设。

(1)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

同一学生的两份试卷成绩组成一对。取第一份减第二份,按绝对差排名后计算负秩和。

答题过程

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Let mDm_D be the population median difference, Paper 1 minus Paper 2. Test H0 ⁣:mD=0H_0\colon m_D=0 against H1 ⁣:mD>0H_1\colon m_D>0. The differences, Paper 1 minus Paper 2, are

 5, 7, −6, 1, −4, 2, 8, 26, −10.\begin{align*} &\,5,\ 7,\ -6,\ 1,\ -4,\\ &\,2,\ 8,\ 26,\ -10. \end{align*}

Ranking their absolute values gives the corresponding signed ranks

 4, 6, −5, 1, −3, 2, 7, 9, −8.\begin{align*} &\,4,\ 6,\ -5,\ 1,\ -3,\\ &\,2,\ 7,\ 9,\ -8. \end{align*}

Thus W−=5+3+8=16W_-=5+3+8=16.

For 99 nonzero differences the lower one-sided 5%5\% critical value is 88. Since 16>816>8, we fail to reject H0H_0. There is insufficient evidence at the 5%5\% level that students tend to score higher on Paper 1 than on Paper 2.

(b)

解法一

思路

展开

检验对配对差值的分布形状作假设。

答题过程

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The population distribution of the paired differences in marks is assumed to be symmetric about its median.