题目
Two companies, P and Q, produce a certain type of paint brush. An independent examiner rates the quality of the brushes produced as poor, satisfactory or good. He takes a random sample of brushes from each company. The examiner’s ratings are summarised in the table.
| Company | Poor | Satisfactory | Good |
|---|---|---|---|
| P | 18 | 43 | 64 |
| Q | 22 | 22 | 31 |
(a) Test, at the 5% significance level, whether quality of brushes is independent of company.
(b) Compare the quality of the brushes produced by the two companies.
题目中文翻译
两家公司 P 和 Q 生产某种油漆刷。一名独立检查员将所生产油漆刷的质量评为差、合格或好。他从每家公司随机抽取油漆刷样本。检查员的评分概括如下表。
| 公司 | 差 | 合格 | 好 |
|---|---|---|---|
| P | 18 | 43 | 64 |
| Q | 22 | 22 | 31 |
(a) 在 5% 显著性水平下,检验油漆刷质量是否与公司相互独立。
(b) 比较两家公司生产的油漆刷质量。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
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先算两个样本的行总数,再根据独立假设求每格期望频数。自由度由表格行列数决定。
答题过程
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Test that brush quality is independent of company against that it is associated with company. The row totals are , the column totals are , and the overall total is . Using row total times column total divided by , the expected counts are
| Company | Poor | Satisfactory | Good |
|---|---|---|---|
| P | 25 | 40.625 | 59.375 |
| Q | 15 | 24.375 | 35.625 |
They all exceed . The statistic is
There are degrees of freedom. The upper critical value is . Since , we reject . There is sufficient evidence at the level that brush quality is associated with company.
(b)
解法一
思路
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两家公司样本量不同,比较各等级的比例。也可结合 (a) 看低质量刷子的频数偏向哪一家公司。
答题过程
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Company P’s brushes tend to be of better quality. In the samples, of P’s brushes were poor compared with of Q’s, and of P’s brushes were good compared with of Q’s.