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CIE 9231 2024 June Paper 42 Q4

A Level / CIE / FS

CIE 9231 2024 June Paper 42 Paper · Question 4

题目

Problem

The random variable YY is the sum of two independent observations of the random variable XX. The probability generating function GY(t)G_Y(t) of YY is given by

GY(t)=t2(43t)4.G_Y(t) = \frac{t^2}{(4 - 3t)^4}.

(a) Find E(Y)E(Y).

[3]

(b) Write down an expression for the probability generating function of XX.

[1]

(c) Find P(X=4)P(X = 4).

[3]
题目中文翻译

随机变量 YY 是随机变量 XX 的两个独立观测值之和。YY 的概率母函数 GY(t)G_Y(t)

GY(t)=t2(43t)4.G_Y(t) = \frac{t^2}{(4 - 3t)^4}.

(a) 求 E(Y)E(Y)

(b) 写出 XX 的概率母函数的一个表达式。

(c) 求 P(X=4)P(X = 4)

解答