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CIE 9231 2025 June Paper 42 Q5

A Level / CIE / FS

CIE 9231 2025 June Paper 42 Paper · Question 5

题目

Problem

Two jigsaw puzzles have the same number of pieces with identical shapes but have different pictures printed on them. One puzzle has a seaside picture and the other has a cartoon picture. A researcher believes that children will complete the cartoon puzzle more quickly. To test this belief, 10 children are randomly selected. The time taken in seconds for each child to complete each puzzle is recorded below.

ChildABCDEFGHIJ
Seaside182130193181192204184192180189
Cartoon161111195159202200168165145160

(a) Carry out a Wilcoxon matched-pairs signed-rank test at the 5% significance level to test the researcher’s belief.

[6]

(b) Show that using a paired-sample sign test at the 5% significance level would result in the opposite conclusion to that found in part (a).

[3]

It was later discovered that the experiment had been conducted such that each child completed the seaside puzzle first followed by the cartoon puzzle.

(c) Comment on the validity of using this experiment to test the researcher’s belief.

[1]
题目中文翻译

两个拼图有相同数量且形状相同的拼块,但上面印着不同的图案。一个拼图是海边图案,另一个是卡通图案。一位研究人员认为儿童完成卡通拼图会更快。为了检验这一观点,随机选取 10 名儿童。每名儿童完成每个拼图所用的时间(单位为秒)记录如下。

儿童ABCDEFGHIJ
海边图案182130193181192204184192180189
卡通图案161111195159202200168165145160

(a) 在 5% 显著性水平下进行 Wilcoxon 配对符号秩检验,检验这位研究人员的观点。

(6)

(b) 证明在 5% 显著性水平下使用配对样本符号检验,会得到与 part (a) 相反的结论。

(3)

后来发现实验的进行方式是:每名儿童都先完成海边图案拼图,然后再完成卡通图案拼图。

(c) 评价使用这个实验来检验研究人员观点的有效性。

(1)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

同一个儿童的两种时间组成一对。用海边减卡通,正差值对应卡通更快。

答题过程

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Let mDm_D be the population median of seaside-minus-cartoon completion times. Test H0 ⁣:mD=0H_0\colon m_D=0 against H1 ⁣:mD>0H_1\colon m_D>0. In child order the differences are 21,19,−2,22,−10,4,16,27,35,2921,19,-2,22,-10,4,16,27,35,29, with signed ranks 6,5,−1,7,−3,2,4,8,10,96,5,-1,7,-3,2,4,8,10,9. The negative rank sum is W−=1+3=4W_-=1+3=4.

The lower one-sided 5%5\% critical value for 1010 nonzero differences is 1010. As 4≤104\le10, we reject H0H_0. There is sufficient evidence at the 5%5\% level that children tend to complete the cartoon puzzle more quickly.

(b)

解法一

思路

展开

符号检验只数正负,不使用差值大小。按同一备择方向算至少观察到八个正差值的概率。

答题过程

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Eight of the ten differences are positive. Under the sign-test null hypothesis, the number SS of positive differences is Binomial⁡(10,1/2)\operatorname{Binomial}(10,1/2). Its upper-tail probability is

 Pr⁡(S≥8)=(108)+(109)+(1010)210= 0.0546875.\begin{align*} &\,\Pr(S\ge8)=\frac{\binom{10}{8}+\binom{10}{9}+\binom{10}{10}}{2^{10}}\\ =&\,0.0546875. \end{align*}

Since this exceeds 0.050.05, the sign test does not reject H0H_0. It gives the opposite decision to the signed-rank test in (a).

(c)

解法一

思路

展开

固定顺序把图案和先后次序混在一起。第二次做题可能受第一次练习的影响。

答题过程

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Every child attempted the cartoon puzzle second, so a shorter time could reflect practice with the pieces rather than the picture. The experiment cannot distinguish the picture effect from the order effect.