题目
A researcher claims that older people take longer to react to a sudden loud noise than younger people. To investigate this, the researcher randomly selects 6 people over 50 years old and 8 people under 25 years old and records their reaction times, in milliseconds, to a sudden loud noise. The reaction times are as follows.
| Over 50 | 198 | 212 | 217 | 229 | 235 | 242 | ||
| Under 25 | 178 | 181 | 183 | 192 | 203 | 209 | 223 | 231 |
Carry out a Wilcoxon rank-sum test at the 5% significance level to test the researcher’s claim.
题目中文翻译
一位研究人员声称,老年人对突然出现的巨大噪声作出反应所需的时间比年轻人更长。为了调查这一点,研究人员随机选取 6 名 50 岁以上的人和 8 名 25 岁以下的人,并记录他们对突然出现的巨大噪声的反应时间,单位为毫秒。反应时间如下。
| 50 岁以上 | 198 | 212 | 217 | 229 | 235 | 242 | ||
| 25 岁以下 | 178 | 181 | 183 | 192 | 203 | 209 | 223 | 231 |
在 5% 显著性水平下进行 Wilcoxon 秩和检验,检验这位研究人员的声称。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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把两组反应时间合并并从大到小排名。若年长组更慢,它的反向秩和应偏小。
答题过程
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Under the common-shape location model, let be that the population medians are equal and that the over-50 population has a higher median. Assigning rank to the smallest time gives the following pooled ranks in the data order.
| Group | Ranks |
|---|---|
| Over 50 | 5, 8, 9, 11, 13, 14 |
| Under 25 | 1, 2, 3, 4, 6, 7, 10, 12 |
The older group’s ascending rank sum is . Reversing the ranks replaces each rank by , giving ranks and sum
A longer reaction time corresponds to a smaller reversed rank, so evidence for the claim is a small value of . For sample sizes and , the lower one-sided critical value for the size- rank sum is . Since , we reject . There is sufficient evidence at the level that the older group tends to take longer to react.