题目
A random sample of 12 observations of a normal random variable is taken. The results give unbiased estimates for the population mean and variance as 10.24 and 0.52 respectively.
Test, at the 10% significance level, the null hypothesis that the population mean is 10.6 against the alternative hypothesis that the population mean is less than 10.6.
题目中文翻译
从一个正态随机变量中抽取容量为 12 的随机样本。结果给出总体均值和总体方差的无偏估计分别为 10.24 和 0.52。
在 10% 显著性水平下,检验原假设“总体均值为 10.6”,备择假设为“总体均值小于 10.6”。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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样本来自正态总体,方差未知。使用自由度 的左尾单样本 检验。
答题过程
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For against , the statistic is
The lower critical value with degrees of freedom is . Since , we reject . There is sufficient evidence at the level that the population mean is less than .