A random sample of 9 observations of a normally distributed random variable X is as follows.
19.421.324.020.718.921.222.523.420.8
The population mean of X is μ.
Test, at the 2.5% significance level, the null hypothesis μ=20 against the alternative hypothesis μ>20.
(6)
题目中文翻译
从服从正态分布的随机变量 X 中随机抽取的 9 个观测值如下。
19.421.324.020.718.921.222.523.420.8
X 的总体均值为 μ。
在 2.5% 的显著性水平下,检验原假设 μ=20,备择假设为 μ>20。
(6)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
The test statistic for H0:μ=20 against H1:μ>20 is
t=s2/9xˉ−20=2.39307….
The upper 2.5% critical value with 8 degrees of freedom is 2.306. Since the statistic is larger, we reject H0. There is sufficient evidence at the 2.5% level that μ>20.