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CIE 9231 2022 Nov Paper 42 Q2

A Level / CIE / FS

CIE 9231 2022 Nov Paper 42 Paper · Question 2

题目

Problem

In the colleges in three regions of a particular country, students are given individual targets to achieve. Their performance is measured against their individual target and graded as ‘above target’, ‘on target’ or ‘below target’. For a random sample of students from each of the three regions, the observed frequencies are summarised in the following table.

PerformanceRegion ARegion BRegion CTotal
Above target624144147
On target1029495291
Below target564561162
Total220180200600

Test, at the 10% significance level, whether performance is independent of region.

[7]
题目中文翻译

在某个国家三个地区的学院中,学生会被给予各自需要达到的个人目标。他们的表现会根据个人目标进行衡量,并被评为“高于目标”、“达到目标”或“低于目标”。从三个地区分别随机抽取学生,观测频数汇总如下表。

表现地区 A地区 B地区 C总计
高于目标624144147
达到目标1029495291
低于目标564561162
总计220180200600

在 10% 显著性水平下,检验表现是否与地区独立。

(7)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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用行、列总数算独立假设下的期望频数。用三行三列确定卡方检验的自由度。

答题过程

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Test H0H_0 that performance relative to target is independent of region against H1H_1 that the variables are associated. Each expected frequency equals its row total times its column total divided by 600600. The expected frequencies are

PerformanceRegion ARegion BRegion C
Above target53.944.149.0
On target106.787.397.0
Below target59.448.654.0

All nine exceed 55. The test statistic is

 χ2=∑(O−E)2E= (62−53.9)253.9+ (41−44.1)244.1+⋯= 4.07652….\begin{align*} &\,\chi^2=\sum\frac{(O-E)^2}{E}\\ =&\,\frac{(62-53.9)^2}{53.9}\\ +&\,\frac{(41-44.1)^2}{44.1}+\cdots\\ =&\,4.07652\ldots. \end{align*}

There are (3−1)(3−1)=4(3-1)(3-1)=4 degrees of freedom. The upper 10%10\% critical value is 7.7797.779. Since 4.07652…<7.7794.07652\ldots<7.779, we fail to reject H0H_0. There is insufficient evidence at the 10%10\% level that performance depends on region.