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CIE 9231 2023 Nov Paper 41 Q2

A Level / CIE / FS

CIE 9231 2023 Nov Paper 41 Paper · Question 2

题目

Problem

A town council has published its plans for redeveloping the town centre and residents are being asked whether they approve or disapprove. A random sample of 250 responses has been selected from residents in the four main streets in the town: North, East, South and West Streets. The results are shown in the table.

North StreetEast StreetSouth StreetWest Street
Approve33544226
Disapprove1939289

Test, at the 5% significance level, whether the opinions of the residents are independent of the streets on which they live.

[7]
题目中文翻译

镇议会公布了重建镇中心的计划,并询问居民是赞成还是反对。从镇上四条主要街道 North、East、South 和 West Streets 的居民中随机抽取了 250 份回应。结果如下表所示。

North StreetEast StreetSouth StreetWest Street
赞成33544226
反对1939289

在 5% 显著性水平下检验居民意见是否与他们居住的街道相互独立。

(7)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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在独立假设下,每个期望频数等于行总数乘列总数再除以总样本量。由列联表的尺寸确定自由度。

答题过程

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Let H0H_0 be that opinion on the plan is independent of street and H1H_1 that the two variables are associated. The row totals are 155155 and 9595, and the column totals are 52,93,70,3552,93,70,35. For example, the expected number approving on North Street is 155(52)/250=32.24155(52)/250=32.24. The expected counts are

OpinionNorthEastSouthWest
Approve32.2457.6643.4021.70
Disapprove19.7635.3426.6013.30

All exceed 55. The statistic is

 χ2=∑(O−E)2E= (33−32.24)232.24+(54−57.66)257.66+⋯= 3.019660….\begin{align*} &\,\chi^2=\sum\frac{(O-E)^2}{E}\\ =&\,\frac{(33-32.24)^2}{32.24}+\frac{(54-57.66)^2}{57.66}+\cdots\\ =&\,3.019660\ldots. \end{align*}

There are (2−1)(4−1)=3(2-1)(4-1)=3 degrees of freedom. The upper 5%5\% critical value is 7.8157.815. Since the statistic is smaller, we fail to reject H0H_0. There is insufficient evidence at the 5%5\% level that residents’ opinions depend on their street.