题目
A school is conducting an experiment to see whether the distance that children can throw a ball increases in hot weather. On a cold day, all the children at the school were asked to throw a ball as far as possible. The distances thrown were measured and recorded. The median distance thrown by a random sample of 25 of the children was 22.0 m. The children were asked to throw the ball again on a hot day. The distances thrown by the same 25 children were measured and recorded and these distances, in m, are shown below.
| 21.2 | 23.5 | 22.9 | 18.6 | 19.4 |
|---|---|---|---|---|
| 22.1 | 26.5 | 20.2 | 25.7 | 20.6 |
| 22.3 | 17.4 | 22.2 | 27.0 | 23.9 |
| 28.2 | 22.6 | 27.2 | 23.0 | 23.7 |
| 19.8 | 22.7 | 23.3 | 21.5 | 24.3 |
The teacher claims that on average the distances thrown will be further when it is hot.
Carry out a Wilcoxon signed-rank test, at the 5% significance level, to test whether the data supports the teacher’s claim.
题目中文翻译
一所学校正在进行实验,研究儿童在炎热天气中投球距离是否会增加。在一个寒冷的日子,学校所有儿童都被要求尽可能远地投球,并测量和记录投球距离。从其中 25 名儿童组成的随机样本中,投球距离的中位数为 22.0 m。随后要求同样的 25 名儿童在炎热的日子再次投球,并测量和记录他们的投球距离。下列数据为这些距离,单位为 m。
| 21.2 | 23.5 | 22.9 | 18.6 | 19.4 |
|---|---|---|---|---|
| 22.1 | 26.5 | 20.2 | 25.7 | 20.6 |
| 22.3 | 17.4 | 22.2 | 27.0 | 23.9 |
| 28.2 | 22.6 | 27.2 | 23.0 | 23.7 |
| 19.8 | 22.7 | 23.3 | 21.5 | 24.3 |
老师声称,平均而言,在炎热天气中投球距离会更远。
在 5% 显著性水平下进行 Wilcoxon 符号秩检验,检验数据是否支持老师的说法。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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按题目给出的冷天中位数 米作为比较基准。对热天数据减去基准,并按差值绝对值排名。
答题过程
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Using m as the reference, test against , where is the population median distance on a hot day. In the order of the hot-day observations, the signed ranks of the differences from are
For the positive alternative, use the negative rank sum . With nonzero, untied differences, the null mean is and the variance is . With the lower-tail continuity correction, the normal statistic is
Since this exceeds the lower critical value , we fail to reject . Using the stated reference, there is insufficient evidence at the level to support the teacher’s claim. The individual cold-day distances would be needed to run a signed-rank test of within-child changes.