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CIE 9709 2026 March Paper 42 Q1

A Level / CIE / M1

CIE 9709 2026 March Paper 42 Paper · Question 1

题目

Problem

A block of mass 200 kg200\,\mathrm{kg} is pulled along rough horizontal ground at a constant speed of v m s−1v\,\mathrm{m\,s^{-1}} by a horizontal rope attached to a winch. The coefficient of friction between the block and the ground is 0.80.8. The winch is working at a constant rate of 4000 W4000\,\mathrm{W}.

Find the value of vv.

(4)
题目中文翻译

一个质量为 200 kg200\,\mathrm{kg} 的物块,由一根连接在绞车上的水平绳拉着,以 v m s−1v\,\mathrm{m\,s^{-1}} 的恒定速率沿粗糙水平地面运动。物块与地面之间的摩擦系数为 0.80.8。绞车以 4000 W4000\,\mathrm{W} 的恒定功率工作。

求 vv 的值。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

解法一

思路

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水平绳不改变正压力,匀速使牵引力等于摩擦力,再用功率关系。

答题过程

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The normal contact force is R=200g=2000 NR=200g=2000\,\mathrm{N}. The frictional force is therefore

F=μR=0.8(2000)=1600 N.F=\mu R=0.8(2000)=1600\text{ N}.

Since the speed is constant, the rope’s tension equals 1600 N1600\,\mathrm{N}. Using power P=TvP=Tv,

4000=1600v,v=2.5.4000=1600v, \qquad \boxed{v=2.5}.