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CIE 9709 2026 March Paper 42 Q4

A Level / CIE / M1

CIE 9709 2026 March Paper 42 Paper · Question 4

题目

Problem

A car of mass 1600 kg1600\,\mathrm{kg} passes through points AA and BB with speeds 10 m s−110\,\mathrm{m\,s^{-1}} and 12 m s−112\,\mathrm{m\,s^{-1}} respectively. The distance ABAB is 2 km2\,\mathrm{km}. The heights of AA and BB above sea level are 250 m250\,\mathrm{m} and 200 m200\,\mathrm{m} respectively. The car’s engine does no work in moving from AA to BB. There are two forces resisting the motion of the car, a braking force and an additional constant force of magnitude 150 N150\,\mathrm{N}.

Use an energy method to find the work done by the braking force as the car moves from AA to BB.

(5)
题目中文翻译

一辆质量为 1600 kg1600\,\mathrm{kg} 的汽车经过点 AA 和 BB 时的速率分别为 10 m s−110\,\mathrm{m\,s^{-1}} 和 12 m s−112\,\mathrm{m\,s^{-1}}。距离 ABAB 为 2 km2\,\mathrm{km}。AA 和 BB 的海拔高度分别为 250 m250\,\mathrm{m} 和 200 m200\,\mathrm{m}。汽车从 AA 行驶至 BB 的过程中,发动机不做功。有两个力阻碍汽车运动:一个制动力,以及一个大小为 150 N150\,\mathrm{N} 的额外恒力。

使用能量方法,求汽车从 AA 行驶至 BB 时制动力所做的功。

(5)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

解法一

思路

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题目指定能量法。势能减少用于增加动能、克服150N阻力及制动耗散,区分两类阻力功。

答题过程

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The decrease in gravitational potential energy is

1600(10)(250−200)=800000 J.1600(10)(250-200)=800000\text{ J}.

The increase in kinetic energy is

12(1600)(122−102)=35200 J.\frac12(1600)(12^2-10^2)=35200\text{ J}.

The work against the additional resistance is 150(2000)=300000 J150(2000)=300000\,\mathrm{J}. Since the engine does no work, the energy removed by braking is

W= 800000−35200−300000= 464800 J.\begin{align*} W=&\,800000-35200-300000\\[4mm] =&\,\boxed{464800\text{ J}}. \end{align*}