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CIE 9709 2022 June Paper 41 Q2

A Level / CIE / M1

CIE 9709 2022 June Paper 41 Paper · Question 2

题目

Problem

Two particles PP and QQ, of masses 0.5 kg0.5\,\mathrm{kg} and 0.3 kg0.3\,\mathrm{kg} respectively, are connected by a light inextensible string. The string is taut and PP is vertically above QQ. A force of magnitude 10 N10\,\mathrm{N} is applied to PP vertically upwards.

Find the acceleration of the particles and the tension in the string connecting them.

(5)

题目中文翻译

质量分别为 0.5 kg0.5\,\mathrm{kg} 和 0.3 kg0.3\,\mathrm{kg} 的两个质点 PP 和 QQ 由一根轻质不可伸长的绳子连接。绳子绷紧,PP 位于 QQ 的正上方。一个大小为 10 N10\,\mathrm{N} 的力竖直向上作用于 PP。

求两质点的加速度及连接它们的绳子中的张力。

(5)

原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

解法一

思路

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整体外力10减总重力,求得两个粒子的共同加速度向上;再对下方Q求张力。

答题过程

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Taking upwards as positive, Newton’s second law for the system gives

10−(0.5+0.3)(10)=(0.5+0.3)a.10-(0.5+0.3)(10)=(0.5+0.3)a.

Thus

a=2.5 m s−2 upwards.\boxed{a=2.5\,\mathrm{m\,s^{-2}}\text{ upwards}}.

For QQ,

T−0.3(10)=0.3(2.5),T=3.75 N.T-0.3(10)=0.3(2.5), \qquad\boxed{T=3.75\,\mathrm{N}}.