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CIE 9709 2023 June Paper 42 Q1

A Level / CIE / M1

CIE 9709 2023 June Paper 42 Paper · Question 1

题目

Problem

A particle of mass 1.6 kg1.6\,\mathrm{kg} is dropped from a height of 9 m9\,\mathrm{m} above horizontal ground. The speed of the particle at the instant before hitting the ground is 12 m s−112\,\mathrm{m\,s^{-1}}.

Find the work done against air resistance.

(3)

题目中文翻译

一个质量为 1.6 kg1.6\,\mathrm{kg} 的质点从水平地面上方 9 m9\,\mathrm{m} 高处由静止释放。质点撞击地面前瞬间的速率为 12 m s−112\,\mathrm{m\,s^{-1}}。

求克服空气阻力所做的功。

(3)

原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

解法一

思路

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空气阻力不必恒定,用初始势能减落地动能,直接求克服阻力的总功。

答题过程

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The loss of gravitational potential energy is 1.6(10)(9)=144 J1.6(10)(9)=144\,\mathrm{J}, and the final kinetic energy is 12(1.6)(122)=115.2 J\tfrac12(1.6)(12^2)=115.2\,\mathrm{J}. Hence the work done against air resistance is

W=144−115.2=28.8 J.\boxed{W=144-115.2=28.8\,\mathrm{J}}.