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CIE 9709 2023 June Paper 42 Q2

A Level / CIE / M1

CIE 9709 2023 June Paper 42 Paper · Question 2

题目

Problem

Two particles AA and BB, of masses 3.2 kg3.2\,\mathrm{kg} and 2.4 kg2.4\,\mathrm{kg} respectively, lie on a smooth horizontal table. AA moves towards BB with a speed of v m s−1v\,\mathrm{m\,s^{-1}} and collides with BB, which is moving towards AA with a speed of 6 m s−16\,\mathrm{m\,s^{-1}}. In the collision the two particles come to rest.

(a) Find the value of vv.

(2)

(b) Find the loss of kinetic energy of the system due to the collision.

(2)

题目中文翻译

两个质点 AA 和 BB 的质量分别为 3.2 kg3.2\,\mathrm{kg} 和 2.4 kg2.4\,\mathrm{kg},位于光滑水平台面上。AA 以 v m s−1v\,\mathrm{m\,s^{-1}} 的速率向 BB 运动,并与 BB 碰撞;BB 正以 6 m s−16\,\mathrm{m\,s^{-1}} 的速率向 AA 运动。碰撞中两个质点均变为静止。

(a) 求 vv 的值。

(2)

(b) 求此次碰撞造成的系统动能损失。

(2)

原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

(a)

解法一

思路

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两粒子相向运动,取A的初始方向为正,碰后总动量为零。

答题过程

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Taking the initial direction of AA as positive, conservation of momentum gives

3.2v+2.4(−6)=0.3.2v+2.4(-6)=0.

Hence

v=14.43.2=4.5.\boxed{v=\frac{14.4}{3.2}=4.5}.

(b)

解法一

思路

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碰后两者都静止,所以损失就是碰前两个动能之和,动能只用速率平方。

答题过程

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The final kinetic energy is zero, so the loss is

L= 12(3.2)(4.52)+12(2.4)(62)= 32.4+43.2= 75.6 J.\begin{align*} L=&\,\frac12(3.2)(4.5^2)+\frac12(2.4)(6^2)\\[4mm] =&\,32.4+43.2\\[4mm] =&\,\boxed{75.6\,\mathrm{J}}. \end{align*}