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CIE 9709 2024 June Paper 42 Q1

A Level / CIE / M1

CIE 9709 2024 June Paper 42 Paper · Question 1

题目

Problem

A cyclist and bicycle have a total mass of 72 kg72\,\mathrm{kg}. The cyclist rides along a horizontal road against a total resistance force of 28 N28\,\mathrm{N}.

Find the total work done by the cyclist to increase his speed from 8 m s−18\,\mathrm{m\,s^{-1}} to 16 m s−116\,\mathrm{m\,s^{-1}} while travelling a distance of 100100 metres.

(3)

题目中文翻译

一名骑车人和自行车的总质量为 72 kg72\,\mathrm{kg}。骑车人沿水平道路骑行,受到的总阻力为 28 N28\,\mathrm{N}。

求骑车人在行进 100100 米的过程中,将速率从 8 m s−18\,\mathrm{m\,s^{-1}} 增加到 16 m s−116\,\mathrm{m\,s^{-1}} 所做的总功。

(3)

原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

Where a numerical value for the acceleration due to gravity (gg) is needed, use 10 m s−210\,\mathrm{m\,s^{-2}}.

需要使用重力加速度 gg 的数值时,取 10 m s−210\,\mathrm{m\,s^{-2}}。

解答

解法一

思路

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总功用于增加动能并克服阻力。这里未说明匀加速,用能量法不需额外假设。

答题过程

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By the work-energy equation,

W=12(72)(162−82)+28(100).W=\frac12(72)(16^2-8^2)+28(100).

Thus

W=6912+2800=9712 J.W=6912+2800=\boxed{9712\,\mathrm{J}}.