题目
A curve, , is such that
The curve passes through the point .
(a) Find in terms of .
(b) The equation of a different curve, , is also such that . This curve instead passes through the point .
Describe, in terms of , the transformation that maps curve onto curve .
题目中文翻译
曲线 满足
且经过点 。
(a) 求用 表示的 的表达式。
(b) 另一条曲线 的方程也满足 ,但该曲线经过点 。
用 描述将曲线 映射到曲线 的变换。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
展开
展开分子后逐项改写成 的幂,再积分并用已知点求常数。
答题过程
展开
For , the derivative is . Integrating gives
At , this is . Setting it equal to gives .
Therefore the required equation is
(b)
解法一
思路
展开
两个曲线的导数相同,所以函数值相差一个常数。比较 时的纵坐标即可。
答题过程
展开
The difference between the two functions is constant on and equals at . Thus is obtained from by the translation with vector