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CIE 9709 2026 March Paper 12 Q9

A Level / CIE / P1

CIE 9709 2026 March Paper 12 Paper · Question 9

题目

Problem

Solve the equation

x23+(8x)13=24.x^{\frac{2}{3}}+(8x)^{\frac{1}{3}}=24.
(4)
题目中文翻译

解方程

x23+(8x)13=24.x^{\frac{2}{3}}+(8x)^{\frac{1}{3}}=24.
(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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设 uu 为 xx 的实数立方根。原式化为二次方程,负的立方根也要保留。

答题过程

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Let u=x3u=\sqrt[3]{x}. Since x2/3=u2x^{2/3}=u^2 and (8x)1/3=2u(8x)^{1/3}=2u, we have

u2+2u−24=(u−4)(u+6)=0.u^2+2u-24=(u-4)(u+6)=0.

Cubing u=4u=4 and u=−6u=-6 gives x=64x=64 and x=−216x=-216. Both satisfy the original equation.