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CIE 9709 2022 June Paper 11 Q8

A Level / CIE / P1

CIE 9709 2022 June Paper 11 Paper · Question 8

题目

Problem

(a) The curve y=sin⁡xy=\sin x is transformed to the curve y=4sin⁡(12x−30∘)y=4\sin\big(\frac12x-30^\circ\big).

Describe fully a sequence of transformations that have been combined, making clear the order in which the transformations are applied.

(5)

(b) Find the exact solutions of the equation 4sin⁡(12x−30∘)=224\sin\big(\frac12x-30^\circ\big)=2\sqrt2 for 0∘≤x≤360∘0^\circ\le x\le360^\circ.

(3)
题目中文翻译

(a) 曲线 y=sin⁡xy=\sin x 经过变换得到曲线 y=4sin⁡(12x−30∘)y=4\sin\big(\frac12x-30^\circ\big)。

完整描述一组组合起来实现这一变换的变换,并明确说明这些变换的实施顺序。

(5)

(b) 求方程 4sin⁡(12x−30∘)=224\sin\big(\frac12x-30^\circ\big)=2\sqrt2 在 0∘≤x≤360∘0^\circ\le x\le360^\circ 范围内的精确解。

(3)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

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先将角度写成 (x−60∘)/2(x-60^\circ)/2。这个形式直接给出先横向拉伸、再右移的一组顺序。

答题过程

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Stretch the graph parallel to the xx-axis by factor 22, giving y=sin⁡(x/2)y=\sin(x/2). Translate it by 6060 units in the positive xx-direction, giving y=sin⁡((x−60∘)/2)y=\sin((x-60^\circ)/2). Then stretch parallel to the yy-axis by factor 44 to obtain the required graph.

解法二

思路

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也可以先将正弦图像右移 3030。随后拉伸时,括号中的整个输入由 xx 换成 x/2x/2。

答题过程

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Translate by 3030 units in the positive xx-direction to obtain y=sin⁡(x−30∘)y=\sin(x-30^\circ). Stretch parallel to the xx-axis by factor 22 to obtain y=sin⁡(x/2−30∘)y=\sin(x/2-30^\circ). Finally stretch parallel to the yy-axis by factor 44.

(b)

解法一

思路

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先把复合角设为一个变量并换算它的范围。找到两个角后再解回 xx。

答题过程

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Let u=x/2−30∘u=x/2-30^\circ. Then −30∘≤u≤150∘-30^\circ\le u\le150^\circ and sin⁡u=2/2\sin u=\sqrt2/2. The two possible values are 45∘45^\circ and 135∘135^\circ. Solving x=2(u+30∘)x=2(u+30^\circ) gives x=150∘x=150^\circ or 330∘330^\circ.