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CIE 9709 2022 June Paper 13 Q10

A Level / CIE / P1

CIE 9709 2022 June Paper 13 Paper · Question 10

题目

Problem

The function f\mathrm{f} is defined by f(x)=(4x+2)−2\mathrm{f}(x)=(4x+2)^{-2} for x>−12x>-\frac12.

(a) Find ∫1∞f(x) dx\displaystyle\int_1^\infty\mathrm{f}(x)\,\mathrm{d}x.

(4)

A point is moving along the curve y=f(x)y=\mathrm{f}(x) in such a way that, as it passes through the point AA, its yy-coordinate is decreasing at the rate of kk units per second and its xx-coordinate is increasing at the rate of kk units per second.

(b) Find the coordinates of AA.

(6)
题目中文翻译

函数 f\mathrm{f} 定义为 f(x)=(4x+2)−2\mathrm{f}(x)=(4x+2)^{-2},其中 x>−12x>-\frac12。

(a) 求 ∫1∞f(x) dx\displaystyle\int_1^\infty\mathrm{f}(x)\,\mathrm{d}x。

(4)

一个点沿曲线 y=f(x)y=\mathrm{f}(x) 运动。当它经过点 AA 时,其 yy 坐标以每秒 kk 个单位的速率递减,其 xx 坐标以每秒 kk 个单位的速率递增。

(b) 求 AA 的坐标。

(6)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

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把无穷上限先换成有限的 TT。求原函数后再让 TT 趋向无穷。

答题过程

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For T>1T>1,

 ∫1T(4x+2)−2 dx= [−14(4x+2)]1T= 124−14(4T+2).\begin{align*} &\,\int_1^T(4x+2)^{-2}\,\mathrm{d}x\\ =&\,\Big[-\frac1{4(4x+2)}\Big]_1^T\\ =&\,\frac1{24}-\frac1{4(4T+2)}. \end{align*}

The last term tends to zero as T→∞T\to\infty, so the improper integral equals 1/241/24.

(b)

解法一

思路

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横坐标以 kk 增加,纵坐标以相同速率减少。用链式法则得到此处曲线斜率为 −1-1。

答题过程

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At AA, the ratio of the rates is (−k)/k=−1(-k)/k=-1. The derivative is −8(4x+2)−3-8(4x+2)^{-3}, so

−8(4x+2)−3= −1,(4x+2)3= 8.\begin{align*} -8(4x+2)^{-3}=&\,-1,\\ (4x+2)^3=&\,8. \end{align*}

This gives x=0x=0, and the height is 2−2=1/42^{-2}=1/4. Thus A=(0,1/4)A=(0,1/4).