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CIE 9709 2023 June Paper 11 Q1

A Level / CIE / P1

CIE 9709 2023 June Paper 11 Paper · Question 1

题目

Problem

Solve the equation 4sin⁡θ+tan⁡θ=04\sin\theta+\tan\theta=0 for 0∘<θ<180∘0^\circ<\theta<180^\circ.

[3]
题目中文翻译

解方程 4sin⁡θ+tan⁡θ=04\sin\theta+\tan\theta=0,其中 0∘<θ<180∘0^\circ<\theta<180^\circ。

[3]

解答

解法一

思路

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先把正切写成正弦除以余弦。题给开区间内正弦始终为正,因此可以约掉它。

答题过程

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The original equation requires cos⁡θ≠0\cos\theta\ne0. Multiplying through by cos⁡θ\cos\theta gives

sin⁡θ(4cos⁡θ+1)=0.\sin\theta(4\cos\theta+1)=0.

Since sin⁡θ>0\sin\theta>0 for 0∘<θ<180∘0^\circ<\theta<180^\circ, we need cos⁡θ=−1/4\cos\theta=-1/4. The unique solution in this interval is θ=104.5∘\theta=104.5^\circ to one decimal place.