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CIE 9709 2023 June Paper 12 Q5

A Level / CIE / P1

CIE 9709 2023 June Paper 12 Paper · Question 5

题目

Problem

The diagram shows the curve with equation y=10x12−52x32y = 10x^{\frac12} - \frac52 x^{\frac32} for x>0x > 0. The curve meets the xx-axis at the points (0,0)(0, 0) and (4,0)(4, 0).

Find the area of the shaded region.

[4]
题目中文翻译

图中显示曲线 y=10x12−52x32y = 10x^{\frac12} - \frac52 x^{\frac32},其中 x>0x > 0。该曲线与 xx 轴相交于点 (0,0)(0, 0) 和 (4,0)(4, 0)。

求阴影区域的面积。

[4]

解答

解法一

思路

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曲线在 00 与 44 之间位于 xx 轴上方。逐项积分,并用在 x=0x=0 的连续端点作为下限。

答题过程

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Since y=52x(4−x)y=\frac52\sqrt{x}(4-x) is positive for 0<x<40<x<4, the area is

 ∫04(10x1/2−52x3/2) dx= [203x3/2−x5/2]04= 1603−32=643.\begin{align*} &\,\int_0^4\Big(10x^{1/2}-\frac52x^{3/2}\Big)\,\mathrm{d}x\\ =&\,\Big[\frac{20}3x^{3/2}-x^{5/2}\Big]_0^4\\ =&\,\frac{160}3-32=\frac{64}3. \end{align*}