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CIE 9709 2024 June Paper 11 Q10

A Level / CIE / P1

CIE 9709 2024 June Paper 11 Paper · Question 10

题目

Problem

The equation of a circle is (x3)2+y2=18(x - 3)^2 + y^2 = 18. The line with equation y=mx+cy = mx + c passes through the point (0,9)(0, -9) and is a tangent to the circle.

Find the two possible values of mm and, for each value of mm, find the coordinates of the point at which the tangent touches the circle.

[8]
题目中文翻译

一个圆的方程为 (x3)2+y2=18(x - 3)^2 + y^2 = 18。方程为 y=mx+cy = mx + c 的直线经过点 (0,9)(0, -9),并且与该圆相切。

mm 的两个可能值,并且对每个 mm 的值,求切线与圆相切点的坐标。

[8]

解答