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CIE 9709 2024 June Paper 11 Q6

A Level / CIE / P1

CIE 9709 2024 June Paper 11 Paper · Question 6

题目

Problem

The function ff is defined by f(x)=2x2+4f(x) = \frac{2}{x^2} + 4 for x<0x < 0. The diagram shows the graph of y=f(x)y = f(x).

(a) On this diagram, sketch the graph of y=f−1(x)y = f^{-1}(x). Show any relevant mirror line.

[2]

(b) Find an expression for f−1(x)f^{-1}(x).

[3]

(c) Solve the equation f(x)=4.5f(x) = 4.5.

[1]

(d) Explain why the equation f−1(x)=f(x)f^{-1}(x) = f(x) has no solution.

[1]
题目中文翻译

函数 ff 定义为 f(x)=2x2+4f(x) = \frac{2}{x^2} + 4,其中 x<0x < 0。图中显示 y=f(x)y = f(x) 的图像。

(a) 在该图上,画出 y=f−1(x)y = f^{-1}(x) 的图像。标出任何相关的镜像线。

[2]

(b) 求 f−1(x)f^{-1}(x) 的表达式。

[3]

(c) 解方程 f(x)=4.5f(x) = 4.5。

[1]

(d) 解释为什么方程 f−1(x)=f(x)f^{-1}(x) = f(x) 无解。

[1]

解答

(a)

解法一

思路

展开

把原图关于 y=xy=x 反射。两条渐近线也交换,反函数在第四象限。

答题过程

展开

Draw the mirror line y=xy=x and reflect the branch across it. Its asymptotes x=0x=0 and y=4y=4 become y=0y=0 and x=4x=4. The inverse branch lies to the right of x=4x=4 and below the xx-axis. For example, (−1,6)(-1,6) reflects to (6,−1)(6,-1).

(b)

解法一

思路

展开

反解 xx 后会出现两个平方根。原定义域是 x<0x<0,所以必须选负根。

答题过程

展开

From y=2/x2+4y=2/x^2+4, we get x2=2/(y−4)x^2=2/(y-4). The original domain requires x<0x<0, and the original range is y>4y>4. Hence

f−1(x)=−2x−4,x>4.f^{-1}(x)=-\sqrt{\frac2{x-4}},\qquad x>4.

(c)

解法一

思路

展开

把 4.54.5 代入反函数,或直接解 2/x2=0.52/x^2=0.5。

答题过程

展开

Since f(x)=4.5f(x)=4.5, x2=4x^2=4. Only x=−2x=-2 lies in the domain.

(d)

解法一

思路

展开

比较两个函数各自可以接收哪些横坐标,也可以直接比较它们的输出符号。

答题过程

展开

The domain of ff is x<0x<0, and that of f−1f^{-1} is x>4x>4. There is no input at which both sides are defined, so the equation has no solution.