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CIE 9709 2024 June Paper 12 Q1

A Level / CIE / P1

CIE 9709 2024 June Paper 12 Paper · Question 1

题目

Problem

The coefficient of x2x^2 in the expansion of (14x)6(1 - 4x)^6 is 1212 times the coefficient of x2x^2 in the expansion of (2+ax)5(2 + ax)^5.

Find the value of the positive constant aa.

[3]
题目中文翻译

(14x)6(1 - 4x)^6 的展开式中 x2x^2 的系数,是 (2+ax)5(2 + ax)^5 的展开式中 x2x^2 的系数的 1212 倍。

求正常数 aa 的值。

[3]

解答