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CIE 9709 2024 June Paper 12 Q2

A Level / CIE / P1

CIE 9709 2024 June Paper 12 Paper · Question 2

题目

Problem

The curve y=x2y = x^2 is transformed to the curve y=4(x−3)2−8y = 4(x - 3)^2 - 8.

Describe fully a sequence of transformations that have been combined, making clear the order in which the transformations have been applied.

[5]
题目中文翻译

曲线 y=x2y = x^2 被变换为曲线 y=4(x−3)2−8y = 4(x - 3)^2 - 8。

完整描述由多个变换组合而成的一组变换,并清楚说明这些变换施加的顺序。

[5]

解答

解法一

思路

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外面的 44 放大纵坐标。平方中的 x−3x-3 对应右移 33,最后的 −8-8 对应下移 88。

答题过程

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A suitable order is:

  1. Stretch by scale factor 44 in the yy-direction to get y=4x2y=4x^2.
  2. Translate by (30)\begin{pmatrix}3\\0\end{pmatrix} to get y=4(x−3)2y=4(x-3)^2.
  3. Translate by (0−8)\begin{pmatrix}0\\-8\end{pmatrix} to get y=4(x−3)2−8y=4(x-3)^2-8.

解法二

思路

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若在伸缩前下移,竖直位移也会乘以 44,因此先下移 22 即可。

答题过程

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First translate by (30)\begin{pmatrix}3\\0\end{pmatrix}, then by (0−2)\begin{pmatrix}0\\-2\end{pmatrix}. This gives y=(x−3)2−2y=(x-3)^2-2. A stretch by scale factor 44 in the yy-direction then gives y=4(x−3)2−8y=4(x-3)^2-8.