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CIE 9709 2024 June Paper 13 Q9

A Level / CIE / P1

CIE 9709 2024 June Paper 13 Paper · Question 9

题目

Problem

The diagram shows the curve with equation y=2x3+10y = \sqrt{2x^3 + 10}.

(a) Find the equation of the tangent to the curve at the point where x=3x = 3. Give your answer in the form ax+by+c=0ax + by + c = 0 where aa, bb and cc are integers.

[5]

(b) The region shaded in the diagram is enclosed by the curve and the straight lines x=1x = 1, x=3x = 3 and y=0y = 0.

Find the volume of the solid obtained when the shaded region is rotated through 360360^\circ about the xx-axis.

[3]
题目中文翻译

图中显示曲线,其方程为 y=2x3+10y = \sqrt{2x^3 + 10}

(a) 求曲线在 x=3x = 3 处的切线方程。答案写成 ax+by+c=0ax + by + c = 0 的形式,其中 aabbcc 是整数。

[5]

(b) 图中阴影区域由曲线以及直线 x=1x = 1x=3x = 3y=0y = 0 围成。

求该阴影区域绕 xx 轴旋转 360360^\circ 所得立体的体积。

[3]

解答