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CIE 9709 2025 June Paper 11 Q7

A Level / CIE / P1

CIE 9709 2025 June Paper 11 Paper · Question 7

题目

Problem

The equation of a curve is y=4x2+9x28y = 4x^2 + \frac{9}{x^2} - 8.

(a) A point PP is moving along the curve in such a way that its yy-coordinate is decreasing at 5 units per second.

Find the rate at which the xx-coordinate of point PP is changing when x=2x = 2.

[4]

(b) Find the coordinates of the stationary points of the curve and determine their nature.

[5]
题目中文翻译

一条曲线的方程为 y=4x2+9x28y = 4x^2 + \frac{9}{x^2} - 8

(a) 点 PP 沿曲线运动,并且其 yy 坐标以每秒 5 个单位的速率减小。

x=2x = 2 时,求点 PPxx 坐标的变化率。

[4]

(b) 求曲线驻点的坐标,并判断其性质。

[5]

解答