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CIE 9709 2025 June Paper 12 Q3

A Level / CIE / P1

CIE 9709 2025 June Paper 12 Paper · Question 3

题目

Problem

The coefficient of x7x^7 in the expansion of (px2+4px)5\left(px^2 + \frac{4}{p}x\right)^5 is 1280.

Find the value of the constant pp.

[4]
题目中文翻译

(px2+4px)5\left(px^2 + \frac{4}{p}x\right)^5 的展开式中,x7x^7 的系数为 1280。

求常数 pp 的值。

[4]

解答