Solve the equation 4sinθtanθ=1+5cosθ for −180∘<θ<180∘.
[6]
题目中文翻译
在 −180∘<θ<180∘ 范围内,解方程 4sinθtanθ=1+5cosθ。
[6]
解答
解法一
思路
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把 tanθ 改写为 sinθ/cosθ。乘以 cosθ 后,用恒等式把方程化为关于余弦的二次式。
答题过程
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The equation is defined only when cosθ=0. Multiplying through by cosθ gives
4sin2θ=cosθ+5cos2θ.
Using sin2θ=1−cos2θ, we obtain 9cos2θ+cosθ−4=0. Thus
cosθ=18−1+145orcosθ=18−1−145.
Both values are in (−1,1) and are nonzero. Cosine is even, so each principal angle and its negative lie in the required interval. The four solutions are −136.4∘, −52.2∘, 52.2∘ and 136.4∘.