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CIE 9709 2026 June Paper 13 Q7

A Level / CIE / P1

CIE 9709 2026 June Paper 13 Paper · Question 7

题目

Problem

The diagram shows the design for a garden. The points AA, BB and CC form the vertices of an equilateral triangle of side length rr metres. The arcs ACAC and ABAB are parts of circles with centres BB and CC respectively and are both of radius rr metres.

(a) Find an expression for the perimeter of the garden. Give your answer in terms of π\pi and rr.

(2)

(b) Given that r=18r=18, find the exact area of the garden. Give your answer in terms of π\pi and 3\sqrt{3}.

(4)
题目中文翻译

图中所示的是一个花园的设计。点 AA、BB 和 CC 构成边长为 rr 米的等边三角形的三个顶点。圆弧 ACAC 和 ABAB 分别属于以 BB 和 CC 为圆心的圆,两者半径均为 rr 米。

(a) 求花园周长的表达式,答案用 π\pi 和 rr 表示。

(2)

(b) 已知 r=18r=18,求花园面积的精确值,答案用 π\pi 和 3\sqrt{3} 表示。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

等边三角形的每个内角都是 π/3\pi/3。边界是两段圆弧和直边 BCBC。

答题过程

展开

Each arc has radius rr and central angle π/3\pi/3, so each length is πr/3\pi r/3. The straight edge BCBC has length rr. Thus the perimeter is

r(1+2π3).r\Big(1+\frac{2\pi}{3}\Big).

(b)

解法一

思路

展开

两个扇形合起来覆盖整座花园,但中间的等边三角形重复计算了一次。把它减去。

答题过程

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The sector at BB and the sector at CC each have area 12r2(π/3)\frac12r^2(\pi/3). Their overlap is triangle ABCABC, with area 12r2sin⁡(π/3)=3r2/4\frac12r^2\sin(\pi/3)=\sqrt3r^2/4. Hence at r=18r=18 the garden area is

182(π3−34)=108π−81318^2\Big(\frac\pi3-\frac{\sqrt3}{4}\Big) =108\pi-81\sqrt3

square metres.